# Line slope calculator 3x-5y=-6

**Straight line given by points A[3; 3] and B[8; 6]**

## Calculation:

**Slope-intercept form of line:**y = 0.6x+1.2

**Canonical form of the line equation:**3x-5y+6 = 0

**Parametric form of the line equation:**

x = 5t+3

y = 3t+3 ; t ∈ R

**Slope:**m = 0.6

**Slope angle of line: φ =**30°57'50″ = 0.5404 rad

**X intercept:**x

_{0}= -2

**Y intercept:**y

_{0}= q = 1.2

**Distance line from the origin:**d

_{0}= 1.029

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(5; 3)

**Normal vector: n =**(3; -5)

**Midpoint of the segment AB: M =**[5.5; 4.5]

**Perpendicular Bisector equation:**5x+3y-41 = 0

**Vector OA = (3; 3) ; |OA| = 4.2426**

**Vector OB = (8; 6) ; |OB| = 10**

**Scalar product OA .OB = 42**

**Angle ∠ AOB = 8°7'48″ = 0.1419 rad**